5+10-5^2=8x+7x/1x-25x

Solution for 5+10-5^2=8x+7x/1x-25x equation:

5+10-5^2=8x+7x/1x-25x

We move all terms to the left:

5+10-5^2-(8x+7x/1x-25x)=0


Domain of the equation: 1x-25x)!=0

x∈R


We add all the numbers together, and all the variables

-(-17x+7x/1x)+5+10-5^2=0

We add all the numbers together, and all the variables

-(-17x+7x/1x)-10=0

We get rid of parentheses

17x-7x/1x-10=0

We multiply all the terms by the denominator


17x*1x-7x-10*1x=0

We add all the numbers together, and all the variables

-7x+17x*1x-10*1x=0

Wy multiply elements

17x^2-7x-10x=0

We add all the numbers together, and all the variables

17x^2-17x=0

a = 17; b = -17; c = 0;
Δ = b2-4ac
Δ = -172-4·17·0
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-17}{2*17}=\frac{0}{34}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+17}{2*17}=\frac{34}{34}
=1
$